Title; Simple Vibration Torsional Oscillation of Flywheel.
Objective; To determine effects for period ( T ) or time taken for one oscillation from
applying a torsional loading to along straight shaft.
Theory;
The flywheels are used to stored energy and to smooth speed fluctuations during a machine cycle. They are served a function similar to that of capacitor in an electric circuit or an accumulator in a hydraulic circuit. In a typical situation, a machine that needs to operate at near constant speed must be matched to a load that produces significant torque fluctuations.
Actually a flywheel is usually an essential component of an internal combustion engine because the cycle includes stroke in which air is being compressed in the cylinder, so the engine is absorbing energy rather than producing it. The flywheels allows energy to be stored during the power strokes when the charge is burning and expending and return to the piston when it compressing the charge.
The torque fluctuations for different cylinders can be evenly distributed over the engine cycle, reducing the output torque fluctuation and reducing the size of the requisite flywheels.
Procedures;
- Firstly, make sure a equipment for experiment for simple vibration torsional of a flywheel complete.
- Then grip the haft firmly between the chuck.
- Measure the length ( L ) of the shaft between the grips.
- The system is set to oscillate for are 10 reading of cycle using the flywheel. The twit angle of the shaft is 150.
- The time taken for the 10 readings of cycles is measured and recorded. The time for one oscillation or period, T I obtained from the reading.
- Step 2 to 5 is repeated for 5 other value of length L, when length, L decrease 5cm. this experiment is end up with a total of six setting of L.
Apparatus;
Heavy steel flywheel, ruler and stop watch.
No. | Length ( cm ) | Cycle |
| Times ( s ) |
| | | | |
1 | 45 | 10 | 15 | 5.75 |
2 | 40 | 10 | 15 | 5.34 |
3 | 35 | 10 | 15 | 5.09 |
4 | 30 | 10 | 15 | 4.72 |
5 | 25 | 10 | 15 | 4.38 |
6 | 20 | 10 | 15 | 4.00 |
Sample calculation;
** No. 1
Length = 45cm
Cycle = 10
O0 = 150
Times1 = 5.75s
Times2 = 5.75 s = 0.58 s
10
t2 = 0.582 = 0.33
Log T = Log 0.58 = - 0.24
Log L = Log 45 = 1.65
Result;
No. | Length ( cm ) | Cycle |
| Times1 ( s ) | Times2 ( s ) | t2 | Log T | Log L |
| | | | | | | | |
1 | 45 | 10 | 15 | 5.75 | 0.58 | 0.33 | - 0.28 | 1.65 |
2 | 40 | 10 | 15 | 5.34 | 0.53 | 0.28 | - 0.28 | 1.60 |
3 | 35 | 10 | 15 | 5.09 | 0.51 | 0.26 | - 0.29 | 1.54 |
4 | 30 | 10 | 15 | 4.72 | 0.47 | 0.22 | - 0.33 | 1.48 |
5 | 25 | 10 | 15 | 4.38 | 0.44 | 0.19 | - 0.36 | 1.40 |
6 | 20 | 10 | 15 | 4.00 | 0.40 | 0.16 | - 0.40 | 1.30 |
Discussion;
From the graph we can know that the graph T2 versus L the largest shaft, longest times we have take it, will cause the flywheel heavy to complete the 10 cycles. Then based on graph Log T versus Log L the resultant of the theory above is same.
Conclusion;
After done the experiment, it can conclude that the longer material we used, it will take a longer time to compete the 10 cycles. The type of material also influences the reading of time. Flywheel is used to stored energy and to smooth speed fluctuations during a machine cycle.
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